The three equations of motion describe anything moving in a straight line with constant acceleration. This calculator takes the initial velocity u, acceleration a and time t and works out the final velocity v and the displacement s.
It also checks the third equation, v² = u² + 2as, which links velocity and displacement without time. These are the SUVAT equations taught in Class 9 and Class 11 physics.
| Initial velocity (u) | 5 m/s |
| Acceleration (a) | 2 m/s² |
| Time (t) | 10 s |
| Final velocity v (m/s) | 25 |
| Displacement s (m) | 150 |
| v² from v² = u² + 2as (m²/s²) | 625 |
| Average velocity (m/s) | 15 |
After 10 s the velocity is 25 m/s and the displacement is 150 m.
Try this example →| Initial velocity (u) | 20 m/s |
| Acceleration (a) | -9.81 m/s² |
| Time (t) | 2 s |
| Final velocity v (m/s) | 0.38 |
| Displacement s (m) | 20.38 |
| v² from v² = u² + 2as (m²/s²) | 0.1444 |
| Average velocity (m/s) | 10.19 |
After 2 s the ball moves at 0.38 m/s (still rising) and is 20.38 m above the start.
Try this example →v = u + at, s = ut + ½at² and v² = u² + 2as. They apply to motion in a straight line with constant acceleration.
s = displacement, u = initial velocity, v = final velocity, a = acceleration and t = time.
About 9.81 m/s² downwards. Take upwards as positive and use a = −9.81 m/s² for a ball thrown up.
Yes. A negative displacement means the object ended up behind its starting point in the direction you chose as positive.